Net 2.0, The
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A 40 kg woman in an elevator is accelerating upward at a rate of 2.0 m/s2.?
Need help with formulas and calcs:
(a) What is the net force acting upon the woman?
(b) What is the gravitational force acting upon the woman?
(c) What is the normal force pushing upward on the woman’s feet?
(a) Use Newton’s law to find the net force acting on her:
Fnet = m*a
(b) The gravitational force on her is found by multiplying her mass by the strength of the gravitational field.
W = m*g
(c) Normal force acts upward on her (felt as her apparent weight, as if she places a scale beneath her feet and weighs herself), gravity acts downward on her. Add these up with upward as positive to find Fnet.
N - W = Fnet
N - m*g = m*a
solve for N:
N = m*(g + a)
————
Data:
m:=40 kg; a:=2.0 m/s^2; g:=9.8 N/kg;
Results:
A) Fnet = 80 Newtons
B) W = 392 Newtons
C) N = 472 Newtons
gintable | Feb 04, 2010
a) the net force = weight(mg) + force due to acceleration(ma) = 40 x 9.8 + 40 x 2 =
b) gravitational force = weight
c) normal force = net force
cunny | Feb 04, 2010